Three methods to solve quadratic equations for GCSE Maths: factorising, the quadratic formula, and completing the square. With worked examples for AQA, Edexcel and OCR.
A quadratic equation is one where the highest power of the variable is 2 — i.e., it contains an x² term. The general form is ax² + bx + c = 0. Solving it means finding the value(s) of x that make the equation true. Quadratics usually have two solutions (roots), but can have one or zero real solutions.
If the quadratic factorises neatly, this is usually the quickest method. Rearrange to ax² + bx + c = 0, factorise the left side, then set each bracket equal to zero.
Solve x² − 5x + 6 = 0
The quadratic formula works for any quadratic, including ones that don't factorise. The formula is: x = (−b ± √(b² − 4ac)) / 2a. Identify a, b, and c from ax² + bx + c = 0, then substitute.
Solve 2x² + 3x − 2 = 0
Completing the square rewrites x² + bx + c as (x + p)² + q. It's useful for finding the turning point of a parabola and for solving quadratics that don't factorise. For x² + bx: half the coefficient of x, square it, then add and subtract.
Solve x² + 6x + 7 = 0 by completing the square
The discriminant (b² − 4ac) tells you how many real solutions a quadratic has before you solve it. It's the expression under the square root in the quadratic formula.
If the quadratic factorises easily, use factorising — it's fastest. If the question says "give your answer to 2 decimal places" or "use the formula", use the quadratic formula. Completing the square is usually only needed if the question explicitly asks for it or asks for the turning point.
Yes — it's not given in the AQA, Edexcel, or OCR formula sheets. Practise writing it from memory: x = (−b ± √(b² − 4ac)) / 2a.
Always rearrange so the right-hand side is 0 before trying any method. For example, x² + 3x = 10 becomes x² + 3x − 10 = 0.
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